Objective - II
1. A situation may be described by using different sets of co-ordinate axes having different orientations. Which of the following do not depend on the orientation of the axes?
(a) the value of a scalar
(b) component of a vector
(c) a vector
(d) the magnitude of a vector
Answer: (a), (c), (d)
Explanation: Sets of co-ordinate axes are simply lines of references to describe the position and orientation of vectors or similar things. Their orientations cannot change (a) the value of scalar, (b) a vector or (d) the magnitude of a vector. But when a vector is resolved along axes, the component is dependent on the angle between the vector and the axis along which it is being resolved. This angle will vary if the orientation of axes is changed. So the component of a vector will depend upon the orientation of the axes.
2. Let vectors C = A + B .
(a) |C| is always greater than |A|
(b) It is always possible to have |C| < |A| and |C| < |B|
(c) C is always equal to A+B
(d) C is never equal to A+B
Answer: (b)
Explanation: Two vectors are added by "parallelogram law of addition" not by mathematical addition. Vectors A and B are placed with their tails at a point without changing their directions. Taking them as two adjacent sides of a parallelogram, the parallelogram and the diagonal from tails is drawn. This diagonal gives the sum of the two vectors. Depending on the directions and magnitudes of two vectors, the length of this diagonal (which represents the magnitude of the sum) may be
(i) greater or less than the magnitude of vector A which makes option (a) false,
(ii) equal to or less than the sum of magnitudes of A and B makes option (c) false,
(iii) equal to the sum of magnitudes of A and B if A and B are collinear and having the same direction. That makes the option (d) false.
Only option (b) is true because it is always possible to have |C| < |A| and |C| < |B| . See this condition in the figure below:-
Sum of two vectors by triangle law of addition |
(a) C must be equal to |A-B|
(b) C must be less than |A-B|
(c) C must be greater than |A-B|
(d) C may be equal to |A-B|
Answer: (c)
Explanation: |A-B| means the numerical difference of the magnitudes of A and B. The answer may be explained through the following diagram:-
The magnitude of resultant and difference of magnitudes of two vectors |
In left figure: In triangle OCD angle ODC =120° so angle COD<120°. Hence OC>CD because in a triangle side opposite the greater angle is greater. So C > |A-B|
In right figure: In triangle OCD angle ODC =120° so angle OCD<120°. Hence OC>OD because in a triangle side opposite the greater angle is greater. So C > |A-B|
4. The x-component of the resultant of several vectors
(a) is equal to the sum of the x-components of the vectors
(b) may be smaller than the sum of the magnitudes of the vectors
(c) may be greater than the sum of the magnitudes of the vectors
(d) may be equal to the sum of the magnitudes of the vectors
Answer: (a), (b), (d)
Explanation: Only (c) is wrong because the sum of the magnitudes of the vectors is the numerical sum while x-component of the resultant vector is the algebraical sum of the x-component of the vectors and will never be greater than the former.
5. The magnitude of the vector product of two vectors A and B may be
(a) greater than AB (b) equal to AB
(c) less than AB (d) equal to zero
Answer: (b), (c), (d)
Explanation: Magnitude of the cross product of two vectors A and B is ABsinθ and value of sinθ varies between 1 to -1. So ABsinθ can vary between AB to -AB ie it can be either equal to or less than AB or even equal to zero. But it can not be greater than AB.
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CHAPTER- 18 - Geometrical Optics
CHAPTER- 17 - Light Waves
CHAPTER- 16 - Sound Waves
OBJECTIVE-I
OBJECTIVE-II
EXERCISES - Q-1 TO Q-10
EXERCISES - Q-11 TO Q-20
EXERCISES -Q-21 TO Q-30
EXERCISES -Q-31 TO Q-40
EXERCISES -Q-41 TO Q-50
EXERCISES -Q-51 TO Q-60
EXERCISES -Q-61 TO Q-70
EXERCISES - Q-71 TO Q-80
EXERCISES - Q-81 TO Q-89
CHAPTER- 15 - Wave Motion and Waves on a String
CHAPTER- 18 - Geometrical Optics
CHAPTER- 16 - Sound Waves
OBJECTIVE-I
OBJECTIVE-II
EXERCISES - Q-1 TO Q-10
EXERCISES - Q-11 TO Q-20
EXERCISES -Q-21 TO Q-30
EXERCISES -Q-31 TO Q-40
EXERCISES -Q-41 TO Q-50
EXERCISES -Q-51 TO Q-60
EXERCISES -Q-61 TO Q-70
EXERCISES - Q-71 TO Q-80
EXERCISES - Q-81 TO Q-89
CHAPTER- 15 - Wave Motion and Waves on a String
CHAPTER- 14 - Fluid Mechanics
Questions for Short Answers
OBJECTIVE-I
OBJECTIVE-II
EXERCISES- Q-1 TO Q-10
EXERCISES- Q-11 TO Q-20
CHAPTER- 13 - Fluid Mechanics
Questions for Short Answers
OBJECTIVE-I
OBJECTIVE-II
EXERCISES Q-1 TO Q-10
EXERCISES- Q11 TO Q20
EXERCISES Q-21 TO Q30
EXERCISES Q-31 TO Q35
CHAPTER- 12 - Simple Harmonic Motion
EXERCISES- Q1 TO Q10
EXERCISES- Q11 TO Q20
EXERCISES- Q21 TO Q30
EXERCISES- Q31 TO Q40
EXERCISES- Q41 TO Q50
EXERCISES- Q51 TO Q58 (2-Extra Questions)
CHAPTER- 11 - Gravitation
EXERCISES -Q 31 TO 39
CHAPTER- 10 - Rotational Mechanics
CHAPTER- 9 - Center of Mass, Linear Momentum, Collision
CHAPTER- 14 - Fluid Mechanics
Questions for Short Answers
OBJECTIVE-I
OBJECTIVE-II
EXERCISES- Q-1 TO Q-10
EXERCISES- Q-11 TO Q-20
CHAPTER- 13 - Fluid Mechanics
Questions for Short Answers
OBJECTIVE-I
OBJECTIVE-II
EXERCISES Q-1 TO Q-10
EXERCISES- Q11 TO Q20
EXERCISES Q-21 TO Q30
EXERCISES Q-31 TO Q35
Questions for Short Answers
OBJECTIVE-II
EXERCISES- Q-1 TO Q-10
EXERCISES- Q-11 TO Q-20
CHAPTER- 13 - Fluid Mechanics
Questions for Short Answers
OBJECTIVE-I
OBJECTIVE-II
EXERCISES Q-1 TO Q-10
EXERCISES- Q11 TO Q20
EXERCISES Q-21 TO Q30
EXERCISES Q-31 TO Q35
CHAPTER- 12 - Simple Harmonic Motion
EXERCISES- Q11 TO Q20
EXERCISES- Q21 TO Q30
EXERCISES- Q31 TO Q40
EXERCISES- Q41 TO Q50
EXERCISES- Q51 TO Q58 (2-Extra Questions)
CHAPTER- 11 - Gravitation
CHAPTER- 10 - Rotational Mechanics
CHAPTER- 9 - Center of Mass, Linear Momentum, Collision
CHAPTER- 8 - Work and Energy
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CHAPTER- 7 - Circular Motion
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CHAPTER- 6 - Friction
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CHAPTER- 6 - Friction
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CHAPTER- 5 - Newton's Laws of Motion
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CHAPTER- 4 - The Forces
The Forces-
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CHAPTER- 3 - Kinematics - Rest and Motion
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CHAPTER- 2 - "Physics and Mathematics"
CHAPTER- 2 - "Physics and Mathematics"
sir question 3 can ve easily understood by formula
ReplyDeleteof course!
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